13)
Phản ứng xảy ra:
\(CuO + {H_2}\xrightarrow{{{t^o}}}Cu + {H_2}O\)
\(ZnO + {H_2}\xrightarrow{{{t^o}}}Zn + {H_2}O\)
\(F{e_3}{O_4} + 4{H_2}\xrightarrow{{{t^o}}}3Fe + 4{H_2}O\)
\(Al_2O_3\) không phản ứng với \ (H_2\).
14)
Phản ứng xảy ra:
\(Zn + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}\)
Ta có:
\({n_{Zn}} = \frac{{19,5}}{{65}} = 0,3{\text{ mol;}}{{\text{n}}_{HCl}} = \frac{{18,25}}{{36,5}} = 0,5{\text{ }}mol\)
\( \to {n_{Zn}} > \frac{1}{2}{n_{HCl}}\)
Vậy \(Zn\) dư
\( \to {n_{Zn{\text{ dư}}}} = 0,3 - \frac{1}{2}.0,5 = 0,05{\text{ mol}}\)
\( \to {m_{Zn}} = 0,05.65 = 3,25{\text{ gam}}\)
\({n_{{H_2}}} = {n_{ZnC{l_2}}} = \frac{1}{2}{n_{HCl}} = 0,25{\text{ mol}}\)
\( \to {m_{ZnC{l_2}}} = 0,25.(65 + 35,5.2) = 34{\text{ gam}}\)
\({V_{{H_2}}} = 0,25.22,4 = 5,6{\text{ lít}}\)
