$ta$ $có$ $:$ $\left \{ {{4x+3y=6} \atop {2x+y=4}} \right.$
$⇒\left \{ {{4x+3y=6} \atop {4x+2y=8}} \right.$
$⇒\left \{ {{y=-2} \atop {2x+y=4}} \right.$
$⇒\left \{ {{y=-2} \atop {2x-2=4}} \right.$
$⇒\left \{ {{y=-2} \atop {2x=6}} \right.$
$⇒\left \{ {{y=-2} \atop {x=3}} \right.$
$Vậy$ $...$