Giải hệ phương trình: \(\left\{ \begin{array}{l}\frac{1}{{{x^2}}} + \frac{1}{{{y^2}}} = 1\\\sqrt {{x^2} - 1} + \sqrt {{y^2} - 1} = \sqrt {xy + 2} \end{array} \right.\)
A.\(\left( {x;\,y} \right) = \left\{ {\left( { - \sqrt 2 ;\,\sqrt 2 } \right);\,\,\left( {\sqrt 2 ;\, - \sqrt 2 } \right)} \right\}\)
B.\(\left( {x;\,y} \right) = \left\{ {\left( {\sqrt 2 ;\,\sqrt 2 } \right);\,\,\left( { - \sqrt 2 ;\,\sqrt 2 } \right)} \right\}\)
C.\(\left( {x;\,y} \right) = \left\{ {\left( { - \sqrt 2 ;\,\sqrt 2 } \right);\,\,\left( { - \sqrt 2 ;\, - \sqrt 2 } \right)} \right\}\)
D.\(\left( {x;\,y} \right) = \left\{ {\left( {\sqrt 2 ;\,\sqrt 2 } \right);\,\,\left( { - \sqrt 2 ;\, - \sqrt 2 } \right)} \right\}\)
A.\(\left( {x;\,y} \right) = \left\{ {\left( { - \sqrt 2 ;\,\sqrt 2 } \right);\,\,\left( {\sqrt 2 ;\, - \sqrt 2 } \right)} \right\}\)
B.\(\left( {x;\,y} \right) = \left\{ {\left( {\sqrt 2 ;\,\sqrt 2 } \right);\,\,\left( { - \sqrt 2 ;\,\sqrt 2 } \right)} \right\}\)
C.\(\left( {x;\,y} \right) = \left\{ {\left( { - \sqrt 2 ;\,\sqrt 2 } \right);\,\,\left( { - \sqrt 2 ;\, - \sqrt 2 } \right)} \right\}\)
D.\(\left( {x;\,y} \right) = \left\{ {\left( {\sqrt 2 ;\,\sqrt 2 } \right);\,\,\left( { - \sqrt 2 ;\, - \sqrt 2 } \right)} \right\}\)
Loga
Hóa Học lớp 12
