Giải hệ phương trình : \( \left \{ \begin{array}{l}2{x^2}y - {y^2}x = 1 \ \8{x^3} - {y^3} = 7 \end{array} \right. \)
A.\(\left( {x;y} \right) = \left( {1;1} \right),\left( {\frac{{ - 1}}{2}; - 2} \right).\)
B.\(\left( {x;y} \right) = \left( {1;-1} \right),\left( {\frac{{ - 1}}{2}; - 2} \right).\)
C.\(\left( {x;y} \right) = \left( {1;1} \right),\left( {\frac{{ - 1}}{2}; 2} \right).\)
D.\(\left( {x;y} \right) = \left( {1;-1} \right),\left( {\frac{{ 1}}{2}; - 2} \right).\)
A.\(\left( {x;y} \right) = \left( {1;1} \right),\left( {\frac{{ - 1}}{2}; - 2} \right).\)
B.\(\left( {x;y} \right) = \left( {1;-1} \right),\left( {\frac{{ - 1}}{2}; - 2} \right).\)
C.\(\left( {x;y} \right) = \left( {1;1} \right),\left( {\frac{{ - 1}}{2}; 2} \right).\)
D.\(\left( {x;y} \right) = \left( {1;-1} \right),\left( {\frac{{ 1}}{2}; - 2} \right).\)
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Hóa Học lớp 12
