$\left \{ {{\frac{x}{2}-\frac{y}{3}=1} \atop {\frac{x}{4}+\frac{2y}{3}=8}} \right.$
⇔$\left \{ {{3x-2y=6} \atop {3x+8y=96}} \right.$
⇔$\left \{ {{-10y=-90} \atop {3x-2y=6}} \right.$
⇔$\left \{ {{y=9} \atop {3x-2.9=6}} \right.$
⇔$\left \{ {{y=9} \atop {3x=24}} \right.$
⇔$\left \{ {{y=9} \atop {x=8}} \right.$
#CHÚC BẠN HỌC TỐT
#2/2/2021