Đáp án:
Ta có
` |2x-1| =` \(\left[ \begin{array}{l}2x-1;(2x-1\ge0)\\1-2x;(1-2x <0)\end{array} \right.\)
` |2x-1| = 2x-1` khi :
` 2x -1 \ge 0`
` => 2x \ge 1`
` => x \ge 1/2`
Đáp án: `x≥\frac{1}{2}`
Giải thích các bước giải:
Do $|a|=a⇔a≥0$
$|a|=-a⇔a<0$
Nên: $|2x-1|=2x-1$
$⇔2x-1≥0$
`⇔x≥\frac{1}{2}`
Bài 20: bỏ dấu ngoặc rồi thu gọn biểu thức: a, A = ( a + b ) - ( a - b ) + ( a - c ) - ( a + c ) b, B = ( a + b - c ) + ( a - b +c ) - ( b + c - a ) - ( a - b - c ) Bài 22: Tính tổng tất cả số nguyên x thỏa mãn: |x| < 2013
Giúp mình bài này với.Cảm ơn nhiều
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Mọi người giúp mình bài này với ạ! Mình đang cần gấp cảm ơn mn nhiều ạ!
âu 4: Cho tam giác ABC cân tại A (góc A < 90 độ). Kẻ BE vuông góc với AC (E thuộc AC), CD vuông góc với AB (D thuộc AB). Gọi I là giao điểm của BE và CD. a/ Chứng minh rằng: ∆ADC = ∆AEB b/ Chứng minh AI là tia phân giác của góc BAC.
Tìm x,y,z biết 5x^2+3y^2+z^2-4x+6xy-4z+6=0 mình đang cần gấp thanks nha
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