a √x-2 =√3-x
x-2=3-x
x-2-3+x=0
2x-5=0
2x=5
x*5/2
b,√2x²-2x+1 =√2-x
2x²-2x+1=2-x
2x²-2x+1-2+x =0
2x²-x-1=0
2x²-2x+x-1=0
2x(x-1)+(x-1) =0
(2x+1)(x-1) -0
\(\left[ \begin{array}{l}x=1\\x=-1/2\end{array} \right.\)
vậy ...
c ,√x²+2x+4 =√2-x
x²+2x+4 =2-x
x²+2x+4-2+x =0
x²+3x+2=0
x²+x+2x+2 =0
x(x+1)+2(x+1)=0
(x+2)(x+1) =0
\(\left[ \begin{array}{l}x=-2\\x=-1\end{array} \right.\)
vậy ...
