Em tham khảo nha :
\(\begin{array}{l}
1)\\
a)\\
CuO + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
{n_{CuO}} = \dfrac{{32}}{{80}} = 0,4mol\\
{n_{{H_2}S{O_4}}} = {n_{CuO}} = 0,4mol\\
{m_{{H_2}S{O_4}}} = 0,4 \times 98 = 39,2g\\
{m_{{\rm{dd}}{H_2}S{O_4}}} = \dfrac{{39,2 \times 100}}{{20}} = 196g\\
b)\\
{m_{{\rm{dd}}spu}} = 32 + 196 = 228g\\
c)\\
{n_{CuS{O_4}}} = {n_{CuO}} = 0,4mol\\
{m_{CuS{O_4}}} = 0,4 \times 160 = 64g\\
C{\% _{CuS{O_4}}} = \dfrac{{64}}{{228}} \times 100\% = 28,1\% \\
2)\\
a)\\
F{e_2}{O_3} + 3{H_2}S{O_4} \to F{e_2}{(S{O_4})_3} + 3{H_2}O\\
{n_{F{e_2}{O_3}}} = \dfrac{{48}}{{160}} = 0,3mol\\
{n_{{H_2}S{O_4}}} = 3{n_{F{e_2}{O_3}}} = 0,9mol\\
{m_{{H_2}S{O_4}}} = 0,9 \times 98 = 88,2g\\
{m_{{\rm{dd}}{H_2}S{O_4}}} = \dfrac{{88,2 \times 100}}{{10}} = 882g\\
b)\\
{m_{{\rm{dd}}spu}} = 882 + 48 = 930g\\
c)\\
{n_{F{e_2}{{(S{O_4})}_3}}} = {n_{F{e_2}{O_3}}} = 0,3mol\\
{m_{F{e_2}{{(S{O_4})}_3}}} = 0,3 \times 400 = 120g\\
C{\% _{F{e_2}{{(S{O_4})}_3}}} = \dfrac{{120}}{{930}} \times 100\% = 12,9\%
\end{array}\)
