Đáp án:
$\dfrac{3^{19}×(-718)}{2^{10}×(2^{20}×5^7+5^{27})}$
Giải thích các bước giải:
$\dfrac{11×3^{32}×3^7-9^{15}}{2^{30}×5^7+2^{10}×5^{27}}$
$=\dfrac{11×3^{32}×3^7-3^{45}}{2^{20}×2^{10}×5^7+2^{10}×5^{27}}$
$=\dfrac{11×3^{39}-3^{39}×3^6}{2^{10}×(2^{20}×5^7+5^{27})}$
$=\dfrac{3^{39}×(11-3^6)}{2^{10}×(2^{20}×5^7+5^{27})}$
$=\dfrac{3^{19}×(-718)}{2^{10}×(2^{20}×5^7+5^{27})}$
$\text{Đến đây mình chịu}$