Đáp án:
c) \(\left[ \begin{array}{l}
x = \dfrac{7}{3}\\
x = \dfrac{3}{2}
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
a)3x = - 2\\
\to x = - \dfrac{2}{3}\\
d)\left( {x + 2} \right)\left( {x + 2 - x + 2} \right) = 0\\
\to 4\left( {x + 2} \right) = 0\\
\to x + 2 = 0 \to x = - 2\\
b)3x\left( {x - 1} \right) + x - 1 = 0\\
\to \left( {x - 1} \right)\left( {3x + 1} \right) = 0\\
\to \left[ \begin{array}{l}
x = 1\\
x = - \dfrac{1}{3}
\end{array} \right.\\
e)2\left( {x + 5} \right) - x\left( {x + 5} \right) = 0\\
\to \left( {x + 5} \right)\left( {2 - x} \right) = 0\\
\to \left[ \begin{array}{l}
x = - 5\\
x = 2
\end{array} \right.\\
c)2x\left( {3x - 7} \right) - 3\left( {3x - 7} \right) = 0\\
\to \left( {3x - 7} \right)\left( {2x - 3} \right) = 0\\
\to \left[ \begin{array}{l}
x = \dfrac{7}{3}\\
x = \dfrac{3}{2}
\end{array} \right.
\end{array}\)
