$\text{Đáp án + Giải thích các bước giải:}$
`c//(x-2)/(3)=x+(1+x)/(2)`
`<=>(2(x-2))/(6)=(6x)/(6)+(3(x+1))/(6)`
`=>2(x-2)=6x+3(x+1)`
`<=>2x-4=6x+3x+3`
`<=>2x-4=9x+3`
`<=>2x-9x=4+3`
`<=>-7x=7`
`<=>x=-1`
`\text{Vậy}` `S={-1}`
`d//(x)/(x+1)+(x+1)/(x-1)=(x^{2}+1)/(x^{2}-1)` `(ĐKXĐ:x\ne±1)`
`<=>(x(x-1))/((x+1)(x-1))+((x+1)^{2})/((x-1)(x+1))=(x^{2}+1)/((x-1)(x+1))`
`=>x(x-1)+(x+1)^{2}=x^{2}+1`
`<=>x^{2}-x+x^{2}+2x+1-x^{2}-1=0`
`<=>x^{2}+x=0`
`<=>x(x+1)=0`
`<=>` \(\left[ \begin{array}{l}x=0\\x+1=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=0(TM)\\x=-1(KTM)\end{array} \right.\)
`\text{Vậy}` `S={0}`
