Câu 1:
a. C2H4+H2O->C2H5OH
b. CH3COOH+Na->CH3COONa+1/2H2
c. CH3COOH+C2H5OH->CH3COOC2H5+H2O
d. CH4+2O2-to->CO2+2H2O
Câu 2:
n CO2 = 8,8/44=0,2(mol) -> m C = 12.0,2=2,4(g)
n H2O = 3,6/18=0,2(mol)->m H = 0,4.1=0,4(g)
Ta có: m C + m H = 2,4+0,4=2,8(g)<6(g)
=> A gồm C,H,O
m O = 6-2,8=3,2(g) => n O =3,2/16=0,2(mol)
Ta có: n C : n H : n O = 0,2:0,4:0,2=1:2:1
->CTĐG: (CH2O)n
Theo đề bài: M A = 30.2=60
=>30n=60<=>n=2
->CTHH: C2H4O2 hay CH3COOH