Đáp án:
$\begin{array}{l}
d){x^2}y{z^2}:{x^2}y = {z^2}\\
e){x^2}y:x{y^2}{z^2}\\
= \dfrac{x}{{y{z^2}}}\\
g){\left( {x + y} \right)^5}:{\left( {x + y} \right)^3}\\
= {\left( {x + y} \right)^2}\\
= {x^2} + 2xy + {y^2}\\
h)3\left( {x - 3} \right):{\left( {3 - x} \right)^2}\\
= 3\left( {x - 3} \right):{\left( {x - 3} \right)^2}\\
= \dfrac{3}{{x - 3}}\\
k)\dfrac{1}{2}{\left( {x + y} \right)^2}:\left( {x + y} \right)\\
= \dfrac{1}{2}\left( {x + y} \right)\\
m) - 27{x^4}{y^2}z:{x^4}y\\
= - 27yz\\
n)5{a^3}b:\left( { - 2{a^2}b} \right)\\
= - \dfrac{5}{2}a\\
y)18{x^2}{y^2}z:\left( { - 6x{y^2}} \right)\\
= - 3xz
\end{array}$
