Em tham khảo nha:
\(\begin{array}{l}
3)\\
a)\\
2C{H_3}COOH + 2Na \to 2C{H_3}COONa + {H_2}\\
b)\\
2C{H_3}COOH + Cu{(OH)_2} \to {(C{H_3}COO)_2}Cu + 2{H_2}O\\
c)\\
C{H_3}COOH + {C_2}{H_5}OH \to C{H_3}COO{C_2}{H_5} + {H_2}O\\
d)\\
2C{H_3}COOH + CaO \to {(C{H_3}COO)_2}Ca + {H_2}O\\
4)\\
a)\\
{n_{C{O_2}}} = \dfrac{{4,48}}{{22,4}} = 0,2\,mol\\
{n_{{H_2}O}} = \dfrac{{5,4}}{{18}} = 0,3\,mol\\
{n_C} = {n_{C{O_2}}} = 0,2\,mol\\
{n_H} = 2{n_{{H_2}O}} = 0,6\,mol\\
{m_O} = 4,6 - 0,2 \times 12 - 0,6 = 1,6g\\
{n_O} = \dfrac{{1,6}}{{16}} = 0,1\,mol\\
{n_C}:{n_H}:{n_O} = 0,2:0,6:0,1 = 2:6:1\\
\Rightarrow CTDGN:{C_2}{H_6}O\\
{M_A} = 23 \times 2 = 46g/mol\\
\Rightarrow 46n = 46 \Rightarrow n = 1\\
CTPT:{C_2}{H_6}O\\
b)\\
CTCT:C{H_3} - C{H_2} - OH
\end{array}\)
