`a)` `x+\frac{3}{7} =\frac{8}{9}`
`x` `=\frac{8}{9}-\frac{3}{7}`
`x` `=\frac{29}{63}`
`b)` `(\frac{3}{10}-x):\frac{2}{5}=\frac{3}{5}`
`\frac{3}{10}-x` `=\frac{3}{5}×\frac{2}{5}`
`\frac{3}{10}-x` `=\frac{6}{25}`
`c)` `\frac{1}{36}(x-\frac{1}{2})^{2}=\frac{1}{9}`
`(x-\frac{1}{2})^{2}=\frac{1}{9}:\frac{1}{36}`
`(x-\frac{1}{2})^{2}=4`
`→` `x-\frac{1}{2}=2`
`x` `=2+\frac{1}{2}`
`x` `=\frac{5}{2}`
`d)` `|2x-3|=5`
`2x-3=5` hay `2x-3=-5`
`2x` `=5+3` `2x` `=-5+3`
`2x` `=8` `2x` `=-2`
`x` `=8:2` `x` `=-2:2`
`x` `=4` `x` `=-1`
Vậy `x=4` hoặc `x=-1`
`e)` `2,5-(\frac{1}{8}x+\frac{1}{2})=\frac{3}{4}`
`\frac{1}{8}x+\frac{1}{2}=2,5-\frac{3}{4}`
`\frac{1}{8}x+\frac{1}{2}=\frac{7}{4}`
`\frac{1}{8}x` `=\frac{7}{4}-\frac{1}{2}`
`\frac{1}{8}x` `=\frac{5}{4}`
`x` `=\frac{5}{4}:\frac{1}{8}`
`x` `=10`
