Đáp án:
$\begin{array}{l}
{x^2} + 2x + 5 = \left( {x - 3} \right)\left| {2 - x} \right|\\
\Rightarrow {\left( {{x^2} + 2x + 5} \right)^2} = {\left( {x - 3} \right)^2}{\left( {2 - x} \right)^2}\\
\Rightarrow {x^4} + 4{x^2} + 25 + 4{x^3} + 10{x^2} + 20x = \left( {{x^2} - 6x + 9} \right)\left( {{x^2} - 4x + 4} \right)\\
\Rightarrow {x^4} + 4{x^2} + 25 + 4{x^3} + 10{x^2} + 20x = \\
{x^4} - 10{x^3} + 37{x^2} - 60x + 36\\
\Rightarrow 14{x^3} + 23{x^2} - 80x + 11 = 0\\
\Rightarrow \left[ \begin{array}{l}
x = - 3,39\\
x = 1,6\\
x = 0,14
\end{array} \right.
\end{array}$
