x+2/2011 + x+2017/4 = x+4/2009 + x+2019/6
⇔ (x+2/2011 + 1) + (x+2017/4 - 1) = (x+4/2009 + 1) + (x+2019/6 - 1)
⇔ x+2013/2011 + x+2013/4 = x+2013/2009 + x+2013/6
⇔ x+2013/2011 + x+2013/4 - x+2013/2009 - x+2013/6 = 0
⇔ (x+2013)(1/2011 + 1/4 - 1/2009 - 1/6) = 0
⇔ x+2013 = 0
⇔ x = -2013
Phương trình có tập nghiệm S={-2013}