Giải phương trình: \(2{\sin ^2}x - 5\sin x + 2 = 0\)
A.\(S = \left\{ {\dfrac{\pi }{6} + k2\pi ;\,\,\dfrac{{5\pi }}{6} + k2\pi |k \in Z} \right\}\).
B.\(S = \left\{ {\dfrac{\pi }{6} + k2\pi ;\,\,-\dfrac{{5\pi }}{6} + k2\pi |k \in Z} \right\}\).
C.\(S = \left\{ {-\dfrac{\pi }{6} + k2\pi ;\,\,\dfrac{{5\pi }}{6} + k2\pi |k \in Z} \right\}\).
D.\(S = \left\{ {-\dfrac{\pi }{6} + k2\pi ;\,\,-\dfrac{{5\pi }}{6} + k2\pi |k \in Z} \right\}\).
A.\(S = \left\{ {\dfrac{\pi }{6} + k2\pi ;\,\,\dfrac{{5\pi }}{6} + k2\pi |k \in Z} \right\}\).
B.\(S = \left\{ {\dfrac{\pi }{6} + k2\pi ;\,\,-\dfrac{{5\pi }}{6} + k2\pi |k \in Z} \right\}\).
C.\(S = \left\{ {-\dfrac{\pi }{6} + k2\pi ;\,\,\dfrac{{5\pi }}{6} + k2\pi |k \in Z} \right\}\).
D.\(S = \left\{ {-\dfrac{\pi }{6} + k2\pi ;\,\,-\dfrac{{5\pi }}{6} + k2\pi |k \in Z} \right\}\).
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Hóa Học lớp 12
