Giải phương trình: \(3 \sin 3x - \sqrt 3 \cos 9x = 1 + 4{ \sin ^3}3x \)
A.\(\left[ \begin{array}{l}x = \frac{\pi }{9} + \frac{{k2\pi }}{9}\\x = \frac{{7\pi }}{{36}} + \frac{{k2\pi }}{9}\end{array} \right.\,\,\,\left( {k \in \mathbb{Z}} \right)\)
B.\(\left[ \begin{array}{l}x = \frac{\pi }{9} + \frac{{k2\pi }}{9}\\x = \frac{{7\pi }}{{54}} + \frac{{k2\pi }}{9}\end{array} \right.\,\,\,\left( {k \in \mathbb{Z}} \right)\)
C.\(\left[ \begin{array}{l}x = \frac{\pi }{{18}} + \frac{{k2\pi }}{9}\\x = \frac{{7\pi }}{{54}} + \frac{{k2\pi }}{9}\end{array} \right.\,\,\,\left( {k \in \mathbb{Z}} \right)\)
D.\(\left[ \begin{array}{l}x = \frac{\pi }{{18}} + \frac{{k2\pi }}{9}\\x = \frac{{7\pi }}{{36}} + \frac{{k2\pi }}{9}\end{array} \right.\,\,\,\left( {k \in \mathbb{Z}} \right)\)