Đáp án:
Giải thích các bước giải:
a)sin2x- √3cosx=1/2
=)1/2sin2x- √3cosx=1/2
=)cos $\pi$/3 sin2x-sin $\pi$/3cosx=1/2
=)sin(2x- $\pi$/3)=1/2
=)sin(2x- $\pi$3)=sin $\pi$/6
=)2x- $\pi$/3= $\pi$/6+k2 $\pi$ hoặc 2x- $\pi$/3= $\pi$- $\pi$/6+k2 $\pi$
=)x= $\pi$/4+k $\pi$ hoặc x=7 $\pi$/12+k $\pi$