Đáp án:
Giải thích các bước giải:
2, x²-9x+20=0
⇔x²-4x-5x+20=0
⇔x(x-4)-5(x-4)=0
⇔(x-5)(x-4)=0
⇔\(\left[ \begin{array}{l}x-5=0\\x-4=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=5\\x=4\end{array} \right.\)
3, 4x²+5x-9=0
⇔4x²-4x+9x-9=0
⇔4x(x-1)+9(x-1)=0
⇔(4x+9)(x-1)=0
⇔\(\left[ \begin{array}{l}4x+9=0\\x-1=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=-$\frac{9}{4}$ \\x=1\end{array} \right.\)