Đáp án:
$\text{(2x+1)(3x-2)= (5x-8)(2x+1) }$
$\text{<=> 6x² - 4x + 3x - 2 = 10x² + 5x - 16x - 8 }$
$\text{<=>6x²-10x² - 4x +3x + 16x - 5x -2+8 =0 }$
$\text{<=> -4x² +10x + 6 =0 }$
$\text{<=> -4x²+12x -2x+6 =0}$
$\text{<=> -4x(x-3) -2(x-3)=0 }$
$\text{<=> (x-3)(-4x-2)=0 }$
$\text{<=> \(\left[ \begin{array}{l}x-3=0\\-4x-2=0\end{array} \right.\) }$
$\text{<=>\(\left[ \begin{array}{l}x=3\\x=\dfrac{-1}{2}\end{array} \right.\) }$
$\text{Vậy phương trình có tập nghiệm S={ 3 ; $\dfrac{-1}{2}$} }$
