Giải phương trình: \(\sin 9x + \sqrt 3 \cos 7x = \sin 7x + \sqrt 3 \cos 9x\)
A.\(x \in \left\{ {k\pi ; - \frac{\pi }{{48}} + \frac{{k\pi }}{8};k \in \mathbb{Z}} \right\}\)
B.\(x \in \left\{ {k\pi ; - \frac{\pi }{{24}} + \frac{{k\pi }}{4};k \in \mathbb{Z}} \right\}\)
C.\(x \in \left\{ {\frac{{k\pi }}{2}; - \frac{\pi }{{48}} + \frac{{k\pi }}{8};k \in \mathbb{Z}} \right\}\)
D.\(x \in \left\{ {\frac{{k\pi }}{2}; - \frac{\pi }{{24}} + \frac{{k\pi }}{4};k \in \mathbb{Z}} \right\}\)
A.\(x \in \left\{ {k\pi ; - \frac{\pi }{{48}} + \frac{{k\pi }}{8};k \in \mathbb{Z}} \right\}\)
B.\(x \in \left\{ {k\pi ; - \frac{\pi }{{24}} + \frac{{k\pi }}{4};k \in \mathbb{Z}} \right\}\)
C.\(x \in \left\{ {\frac{{k\pi }}{2}; - \frac{\pi }{{48}} + \frac{{k\pi }}{8};k \in \mathbb{Z}} \right\}\)
D.\(x \in \left\{ {\frac{{k\pi }}{2}; - \frac{\pi }{{24}} + \frac{{k\pi }}{4};k \in \mathbb{Z}} \right\}\)
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Hóa Học lớp 12
