Giải thích các bước giải:
a)
⇔$\left \{ {{x - 6 ≥ 0} \atop {5x+6=(x-6)^{2} }} \right.$
⇔$\left \{ {{x≥-6} \atop {5x+6=x^2-12x+36}} \right.$
⇔$\left \{ {{x≥-6} \atop {-x^2+17x-30=0}} \right.$
⇔$\left \{ {{x≥-6} \atop {\left[ \begin{array}{l}x=15(TM)\\x=2(L)\end{array} \right.\ }} \right.$
c)
⇔ $\left \{ {{x-2≥0} \atop {2x-3=(x-2)^2}} \right.$
⇔$\left \{ {{x≥2} \atop {2x-3=x^2-4x+4}} \right.$
⇔$\left \{ {{x≥2} \atop {-x^2+6x-7=0}} \right.$
⇔$\left \{ {{x≥2} \atop { \left[ \begin{array}{l}x=3+\sqrt{2}(TM) \\x=3-\sqrt{2}(L) \end{array} \right.\ }} \right.$
