Câu 2 bạn xem lại đề vì KQ xấu
1)
ĐK: $x-3\ne 0\to x\ne 3$
$\dfrac{x-1}{x-3}>-1$
$\to \dfrac{x-1}{x-3}+1>0$
$\to \dfrac{x-1+x-3}{x-3}>0$
$\to \dfrac{2x-4}{x-3}>0$
$\to \dfrac{x-2}{x-3}>0$
$\to \left[ \begin{array}{l}x-2>0; x-3>0 \\x-2<0; x-3<0\end{array} \right.$
$\to \left[ \begin{array}{l}x<2\\x>3\end{array} \right.$