#LC
`sin(π/3 -3x) = 1/2`
⇔`sin(π/3 -3x) = sin(π/6)`
⇔\(\left[ \begin{array}{l}\frac{π}{3} -3x=\frac{π}{6}+k2π\\\frac{π}{3} -3x=\frac{5π}{6}+k2π\end{array} \right.\)
⇔\(\left[ \begin{array}{l}3x=\frac{π}{6}+k2π\\3x=\frac{-π}{2}+k2π\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=\frac{π}{18}+k\frac{2π}{3}\\x=\frac{-π}{6}+k\frac{2π}{3}\end{array} \right.\)
