Đáp án:
a) $C_3H_8$ và $C_4H_{10}$
b) $60\%$ và $40\%$
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
Mankan = 24,8 \times 2 = 49,6g/mol\\
14n + 2 = 49,6\\
= > n = 3,4\\
= > CTHH:{C_3}{H_8},{C_4}{H_{10}}\\
b)\\
M{C_3}{H_8} = 44\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,8,4\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \searrow \,\,\,\,\,\,\,\,\,\,\, \nearrow \\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,49,6\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \nearrow \,\,\,\,\,\,\,\,\,\,\, \searrow \\
M{C_4}{H_{10}} = 58\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,5,6\\
\frac{{n{C_3}{H_8}}}{{n{C_4}{H_{10}}}} = \frac{{8,4}}{{5,6}} = \frac{3}{2}\\
\% V{C_3}{H_8} = \frac{3}{5} \times 100\% = 60\% \\
\% V{C_4}{H_{10}} = 100 - 60 = 40\%
\end{array}\)
