6.1
$(-C_6H_{10}O_5-)_n\to nC_6H_{12}O_6\to 2nC_2H_5OH$
$m_{(-C_6H_{10}O_5-)_n}=1.90\%=0,9$ tấn $=900kg$
Cứ $162n$ kg xenlulozơ tạo $46.2n=92n$ kg etanol.
$\Rightarrow m_{C_2H_5OH}=\dfrac{900.92}{162}.85\%=434,4kg$
$D_{C_2H_5OH}=0,8kg/l\Rightarrow V_{\text{rượu 45 độ}}=\dfrac{434,4}{0,8}:45\%=1206,67l$
6.2
$(-C_6H_{10}O_5-)_n\to nC_6H_{12}O_6\to 2nC_2H_5OH$
$m_{(-C_6H_{10}O_5-)_n}=1.90\%=0,9$ tấn $=900kg$
Cứ $162n$ kg tinh bột tạo $180n$ kg glucozơ.
$\Rightarrow m_{C_6H_{12}O_6}=\dfrac{900.180}{162}.85\%=850$ kg
Cứ $180n$ kg glucozơ tạo $46n.2=92n$ kg etanol.
$\Rightarrow m_{C_2H_5OH}=\dfrac{850.92}{180}.85\%=369,27kg$
$D_{C_2H_5OH}=0,8kg/l\Rightarrow V_{\text{rượu 70 độ}}=\dfrac{369,27}{0,8}:70\%=659,41l$
6.3
$V_{C_2H_5OH}=1.40\%=0,4l$
$\Rightarrow m_{C_2H_5OH}=0,4.0,8=0,32kg$
$(-C_6H_{10}O_5-)_n\to 2nC_2H_5OH$
$\Rightarrow m_{(-C_6H_{10}O_5-)_n}=\dfrac{162n.0,32}{92n}:80\%=0,7kg$
$\to m_{\text{khoai}}=0,7.2=1,4kg$
