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thuquangvinh2009

2 năm trước

Loga Sinh Học lớp 12

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hh0166781

Giải thích các bước giải:

$\begin{array}{l}1) 5-3x=6x+7\\⇒-9x=2\\⇒x=-\dfrac{2}{9}\\\text{Vậy $x=-\dfrac{2}{9}$}\\2) 11-2x=x-1\\⇒-3x=-12\\⇒x=4\\\text{Vậy $x=4$}\\3) 12-2(2x-5)=3(3-x)\\⇒12-4x+10=9-3x\\⇒-x=-13\\⇒x=13\\\text{Vậy $x=13$}\\4) 2(x-1)+5=3(2-x)+7\\⇒2x-2+5=6-3x+7\\⇒2x+3=-3x+13\\⇒x=2\\\text{Vậy $x=2$}\\5) (x+2)^2+5=(x+1)(x-1)\\⇒x^2+4x+4+5=x^2-1\\⇒x^2+4x+9=x^2-1\\⇒4x+9=-1\\⇒x=-\dfrac{5}{2}\\\text{Vậy $x=-\dfrac{5}{2}$}\\6)(x-2)(x-3)+3x^2=(2x-1)^2\\⇒x^2-5x+6+3x^2=4x^2-4x+1\\⇒4x^2-5x+6=4x^2-4x+1\\⇒-5x+6=-4x+1\\⇒-x=-5\\⇒x=5\\\text{Vậy $x=5$}\\7)\dfrac{2x-1}{3}=\dfrac{x+2}{4}\\⇒\dfrac{4(2x-1)}{12}=\dfrac{3(x+2)}{12}\\⇒8x-4=3x+6\\⇒5x=10\\⇒x=2\\\text{Vậy $x=2$}\\8)\dfrac{3x-2}{3}=\dfrac{3-2x}{2}\\⇒\dfrac{2(3x-2)}{6}=\dfrac{3(3-2x)}{6}\\⇒6x-4=9-6x\\⇒12x=13\\⇒x=\dfrac{13}{12}\\\text{Vậy $x=\dfrac{13}{12}$}\\9)1-\dfrac{2x-5}{6}=\dfrac{3-x}{4}\\⇒\dfrac{24}{24}-\dfrac{4(2x-5)}{24}=\dfrac{6(3-x)}{24}\\⇒24-8x+20=18-6x\\⇒-2x=-26\\⇒x=13\\\text{Vậy $x=13$}\\10)\dfrac{x+1}{3}-\dfrac{x-2}{6}=\dfrac{2x-1}{2}\\⇒\dfrac{2(x+1)}{6}-\dfrac{x-2}{6}=\dfrac{3(2x-1)}{6}\\⇒2x+2-x+2=6x-3\\⇒x+4=6x-3\\⇒-5x=-7\\⇒x=\dfrac{7}{5}\\\text{Vậy $x=\dfrac{7}{5}$}\end{array}$

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dangnuvietlinh2

`1, 5-3x=6x+7`

`<=> 6x+3x=5-7`

`<=> 9x=-2`

`<=> x=-2/9`

Vậy `x=-2/9`

`2, 11-2x=x-1`

`<=> x+2x=11+1`

`<=> 3x=12`

`<=> x=4`

Vậy `x=4`

`3, 12-2(2x-5)=3(3-x)`

`<=> 12-4x+10=9-3x`

`<=> 22-4x=9-3x`

`<=> -3x+4x=22-9`

`<=> x=13`

Vậy `x=13`

`4, 2(x-1)+5=3(2-x)+7`

`<=> 2x-2+5=6-3x+7`

`<=> 2x+3=13-3x`

`<=> 2x+3x=13-3`

`<=> 5x=10`

`<=> x=2`

Vậy `x=2`

`5, (x+2)^2+5=(x-1)(x+1)`

`<=> x^2+4x+4+5=x^2-1`

`<=> 4x+9=-1`

`<=> 4x=-10`

`<=> x=-5/2`

Vậy `x=-5/2`

`6, (x-2)(x-3)+3x^2=(2x-1)^2`

`<=> x^2-3x-2x+6+3x^2=4x^2-4x+1`

`<=> 4x^2-5x+6=4x^2-4x+1`

`<=> -5x+6=-4x+1`

`<=> -4x+5x=6-1`

`<=> x=5`

Vậy `x=5`

`7, (2x-1)/3=(x+2)/4`

`<=> 4(2x-1)=3(x+2)`

`<=> 8x-4=3x+6`

`<=> 8x-3x=6+4`

`<=> 5x=10`

`<=> x=2`

Vậy `x=2`

`8, (3x-2)/3=(3-2x)/2`

`<=> 2(3x-2)=3(3-2x)`

`<=> 6x-4=9-6x`

`<=> 12x=13`

`<=> x=13/12`

Vậy `x=13/12`

`9, 1-(2x-5)/6=(3-x)/4`

`<=> (6-2x+5)/6=(3-x)/4`

`<=> (11-2x)/6=(3-x)/4`

`<=> 6(3-x)=4(11-2x)`

`<=> 18-6x=44-8x`

`<=> -6x+8x=44-18`

`<=> 2x=26`

`<=> x=13`

Vậy `x=13`

`10, (x+1)/3-(x-2)/6=(2x-1)/2`

`<=> (2(x+1))/6-(x-2)/6=(3(2x-1))/6`

`=> 2x+2-x+2=6x-3`

`<=> x+4=6x-3`

`<=> 6x-x=4+3`

`<=> 5x=7`

`<=> x=7/5`

Vậy `x=7/5`

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