cau 1 a, 10010(2)=18(10) cau2 a, 3CB(16)=971(10)
b, 1100110(2)=102(10) b, 1A2D(16)=6701(10)
c, 10010101(2)=149(10) c, A5FC(16)=42492(10)
cau2 a, 125(10)=1111101(2)
b, 8125(10)=1FBD(16)
bam mode +4
bin la co so 2
oct la co so 8
dec la co so 10
hex la co so 16