Đáp án+Giải thích các bước giải:
`b)`
`2(x-1)(x^2+x+1)+6(x-1)^2=32+2(x+1)^3`
`⇔2(x^3-1)+6(x^2-2x+1)=32+2(x^3+3x^2+3x+1)`
`⇔2x^3-2+6x^2-12x+6=32+2x^3+6x^2+6x+2`
`⇔2x^3+6x^2-12x+4=2x^3+6x^2+6x+34`
`⇔2x^3+6x^2-12x-2x^3-6x^2-6x=34-4`
`⇔-18x=30`
`⇔x=-30/18`
`⇔x=-5/3`
Vậy `x=-5/3`
`c)`
`(x+3)(x^2-3x+9)-x(x-4)(x+4)=59`
`⇔x^3+3^3-x(x^2-4^2)=59`
`⇔x^3+27-x(x^2-16)=59`
`⇔x^3+27-x^3+16x=59`
`⇔16x+27=59`
`⇔16x=32`
`⇔x=2`
Vậy `x=2`
