$\displaystyle\int \dfrac{2}{(x+1)^2}dx$
$=-2\displaystyle\int\dfrac{-1}{(x+1)^2}dx$
$=-2.\dfrac{1}{x+1}+C$
$=\dfrac{-2}{x+1}+C$
$\displaystyle\int \sqrt{1-2x}dx$
$=\displaystyle\int (1-2x)^{\frac{1}{2}}dx$
$=\dfrac{1}{-2}.\dfrac{(1-2x)^{\frac{3}{2}} }{\dfrac{3}{2}}+C$
$=\dfrac{-3}{4}\sqrt{1-2x}^3+C$