Đáp án:
$\\$
`a,`
`|x-1| - 2/3 = 1 3/5`
`↔ |x-1| - 2/3 = 8/5`
`↔ |x-1| = 8/5 + 2/3`
`↔ |x-1| = 34/15`
`↔` \(\left[ \begin{array}{l}x-1=\dfrac{34}{15}\\x-1=\dfrac{-34}{15}\end{array} \right.\)
`↔` \(\left[ \begin{array}{l}x=\dfrac{34}{15}+1\\x=\dfrac{-34}{15}+1\end{array} \right.\)
`↔` \(\left[ \begin{array}{l}x=\dfrac{49}{15}\\x=\dfrac{-19}{15}\end{array} \right.\)
Vậy `x=49/15` hoặc `x=(-19)/15`
$\\$
`b,`
`|x + 3/4| + 1/3 = 5/6`
`↔ |x + 3/4| = 5/6 - 1/3`
`↔ |x + 3/4| =1/2`
`↔` \(\left[ \begin{array}{l}x+\dfrac{3}{4}=\dfrac{1}{2}\\x+\dfrac{3}{4}=\dfrac{-1}{2}\end{array} \right.\)
`↔` \(\left[ \begin{array}{l}x=\dfrac{1}{2}-\dfrac{3}{4}\\x=\dfrac{-1}{2}-\dfrac{3}{4}\end{array} \right.\)
`↔` \(\left[ \begin{array}{l}x=\dfrac{-1}{4}\\x=\dfrac{-5}{4}\end{array} \right.\)
Vậy `x=(-1)/4` hoặc `x=(-5)/4`
$\\$
`c,`
`9/2- [2/3 - (x + 7/4)] = (-5)/4`
`↔ 2/3 - (x+ 7/4) = 9/2 - (-5)/4`
`↔ 2/3 - (x + 7/4) = 23/4`
`↔ x + 7/4 = 2/3 - 23/4`
`↔ x + 7/4 = (-61)/12`
`↔ x = (-61)/12 - 7/4`
`↔ x = (-41)/6`
Vậy `x=(-41)/6`
$\\$
`d,`
`4/3 - (x - 1/5) = | (-3)/10 + 1/2| - 1/6`
`↔ 4/3 - (x-1/5) = |1/5| - 1/6`
`↔ 4/3 - (x-1/5) = 1/5 - 1/6`
`↔ 4/3 - (x-1/5)=1/30`
`↔ x - 1/5 = 4/3 - 1/30`
`↔ x - 1/5 = 13/10`
`↔ x = 13/10 + 1/5`
`↔ x =3/2`
Vậy `x=3/2`
