`A = {-4; -3; -2; -1; 0; 1; 2}`
`B = {0; 1; 2; 3; 4; 5}`
`(2x - 3)(x^2 - 4) = 0`
`<=> (2x - 3)(x - 2)(x + 2) = 0`
`<=>` \(\left[ \begin{array}{l}2x - 3 = 0\\x - 2 = 0\\x + 2 = 0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = \dfrac{3}{2}\\x = ±2\end{array} \right.\)
`=> C = {2}`
`(2 - x)(2x^2 - 3x + 1) = 0`
`<=>` \(\left[ \begin{array}{l}2 - x = 0\\2x^2 - 3x + 1 = 0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = 2\\x = 1\\x = \dfrac{1}{2}\end{array} \right.\)
`=> D = {1; 2}`
`(3x - 2)(x^2 - 2x - 1) = 0`
`<=>` \(\left[ \begin{array}{l}3x - 2 = 0\\x^2 - 2x - 1 = 0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = \dfrac{2}{3}\\x = 1 + \sqrt{2}\\x = 1 - \sqrt{2}\end{array} \right.\)
`=> E = {2/3}`
`(2x - 1)(x^2 - 3x - 2) = 0`
`<=>` \(\left[ \begin{array}{l}2x - 1 = 0\\x^2 - 3x - 2 = 0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x = \dfrac{1}{2}\\x = \dfrac{3 + \sqrt{17}}{2}\\x = \dfrac{3 - \sqrt{17}}{2}\end{array} \right.\)
`=> F = {1/2; (3 + \sqrt{17})/2; (3 - \sqrt{17})/2}`
