Em tham khảo nha :
\(\begin{array}{l}
11)\\
BaO + {H_2}O \to Ba{(OH)_2}\\
{N_{BaO}}:{N_{{H_2}O}} = 1:1\\
12)\\
4Al + 3{O_2} \xrightarrow{t^0} 2A{l_2}{O_3}\\
{N_{Al}}:{N_{{O_2}}} = 4:3\\
13)\\
Cu + 2AgN{O_3} \to Cu{(N{O_3})_2} + 2Ag\\
{N_{Cu}}:{N_{AgN{O_3}}} = 1:2\\
14)\\
2NaOH + {H_2}S{O_4} \to N{a_2}S{O_4} + 2{H_2}O\\
{N_{NaOH}}:{N_{{H_2}S{O_4}}} = 2:1\\
15)\\
2KCl{O_3} \xrightarrow{t^0} 2KCl + 3{O_2}\\
{N_{KCl}}:{N_{{O_2}}} = 2:3\\
16)\\
2Na + C{l_2} \xrightarrow{t^0} 2NaCl\\
{N_{Na}}:{N_{C{l_2}}} = 2:1\\
17)\\
F{e_2}{(S{O_4})_3} + 6KOH \to 2Fe{(OH)_3} + 3{K_2}S{O_4}\\
{N_{F{e_2}{{(S{O_4})}_3}}}:{N_{KOH}} = 1:6
\end{array}\)
