Em tham khảo nha :
\(\begin{array}{l}
{C_4}{H_{10}} \xrightarrow{t^0,xt} C{H_4} + {C_3}{H_6}\\
2C{H_4} \xrightarrow{t^0,làm lạnh nhanh} {C_2}{H_2} + 2{H_2}\\
{C_2}{H_2} + HCl \xrightarrow{t^0,áp suất,xt} C{H_2} = CHCl\\
nC{H_2} = CHCl \xrightarrow{t^0,áp suất,xt} {( - C{H_2} - CHCl - )_n}
\end{array}\)