Giải thích các bước giải:
\(\begin{array}{l}
5.\\
2NaOH + {H_2}S{O_4} \to N{a_2}S{O_4} + 2{H_2}O\\
{n_{{H_2}S{O_4}}} = 0,005mol\\
\to {n_{NaOH}} = \dfrac{1}{2}{n_{{H_2}S{O_4}}} = 0,005mol\\
\to C{M_{NaOH}} = \dfrac{{0,005}}{{0,05}} = 0,1M\\
6.\\
CuO + {H_2}S{O_4} \to CuS{O_4} + {H_2}O\\
{n_{CuO}} = 0,2mol\\
\to {n_{{H_2}S{O_4}}} = {n_{CuO}} = 0,2mol\\
\to {m_{{H_2}S{O_4}}} = 19,6g\\
\to {m_{{\rm{dd}}{H_2}S{O_4}}} = \dfrac{{19,6}}{{10\% }} \times 100\% = 196g\\
\to {n_{{\rm{CuS}}{O_4}}} = {n_{CuO}} = 0,2mol\\
\to {m_{{\rm{CuS}}{O_4}}} = 32g\\
\to {m_{{\rm{dd}}thuduoc}} = {m_{{\rm{dd}}{H_2}S{O_4}}} + {m_{CuO}} = 212g\\
\to C{\% _{{\rm{CuS}}{O_4}}} = \dfrac{{32}}{{212}} \times 100\% = 15,09\%
\end{array}\)
