$m_C$=$\frac{0,224}{22,4}$$.12=0,12g$
$m_H$=$\frac{0,18}{18}$.$2=0,02g$
$m_O$=$0,3-0,12-0,2=0,16g$
$CxHyOz$:
$x:y:z$=$\frac{0,12}{12}$: $\frac{0,02}{1}$ :$\frac{0,16}{16}$
=$0,01:0,02:0,01$
=$1:2:1$
⇒ $CH_2O$
CTDGN: $(CH_2O)n$
Ta có :
$(12+1.2+16)n=60$
⇒ $30n=60$
⇒ $n=2$
⇒ $C_2H_4O_2$