Đáp án: vote 5 * cho mk nhé
Giải thích các bước giải:
m1=38kg;v1=1m/s;m2=2kg;v2=7m/s;m1=38kg;v1=1m/s;m2=2kg;v2=7m/s;
a> ngược chiều:
P=|P1−P2|<=>(m1+m2).v=|m1.v1−m2.v2|=>v=|38−2.7|38+2=0,6m/sP=|P1−P2|<=>(m1+m2).v=|m1.v1−m2.v2|=>v=|38−2.7|38+2=0,6m/s
b>
P=P1+P2<=>(m1+m2).v=m1.v1+m2.v2=>v=38+2.738+2=1,3m/sP=P1+P2<=>(m1+m2).v=m1.v1+m2.v2=>v=38+2.738+2=1,3m/s
2>
{m_p}.{v_p} = {\rm{ \;}} - {m_p}.v_p^' + {m_\alpha }.v_\alpha ^'{m_p}.{v_p} = {\rm{ \;}} - {m_p}.v_p^' + {m_\alpha }.v_\alpha ^'
=>mα=1,67.10−27.107+1,67.10−27.6.1064.106=6,68.10−27kg∖)=>mα=1,67.10−27.107+1,67.10−27.6.1064.106=6,68.10−27kg∖)
3>
P2+P22=P21<=>((m1+m2).v)2+(m2.v2)2=(m1.v1)2P2+P22=P12<=>((m1+m2).v)2+(m2.v2)2=(m1.v1)2
P2+P22=P21<=>((m1+m2).v)2+(m2.v2)2=(m1.v1)2=>v1=√((m1+m2).v)2+(m2.v2)2m21=√((8+4).100)2+(4.225)282=187,5m/s
