Đáp án:
Giải thích các bước giải:
$9x^2-1=(3x-1)(5x+8)$
$(=)(3x-1)(3x+1)-(3x-1)(5x+8)=0$
$(=)(3x-1)(3x+1-5x-8)=0$
$(=)(3x-1)(-2x-7)=0$
\(\left[ \begin{array}{l}3x-1=0\\-2x-7=0\end{array} \right.\)
=>\(\left[ \begin{array}{l}x=\dfrac{1}{3}\\x=-\dfrac{7}{2}\end{array} \right.\)
$9^2-1=(3x-1)(5x+8)$
$3x(5x+8)-(5x+8)=80$
$(=)15x^2+24x-5x-8-80=0$
$(=)15x^2+19x-88=0$