Hướng dẫn giải:
ĐKXĐ: `x\ne0;x\ne+-3;x\ne-3/2`
`x/(x-3)-(x^2+3x)/(2x+3).((x+3)/(x^2-3x)-x/(x^2-9))`
`=x/(x-3)-(x(x+3))/(2x+3).[(x+3)/(x(x-3))-x/((x+3)(x-3))]`
`=x/(x-3)-(x(x+3))/(2x+3).((x+3)^2-x^2)/(x(x+3)(x-3))`
`=x/(x-3)-(x^2+6x+9-x^2)/((2x+3)(x-3))`
`=x/(x-3)-(3(2x+3))/((2x+3)(x-3))`
`=x/(x-3)-3/(x-3)`
`=(x-3)/(x-3)`
`=1`