Đáp án:
d) \(x = \dfrac{{22}}{{13}}\)
Giải thích các bước giải:
\(\begin{array}{l}
a) - \dfrac{1}{6}x = \dfrac{2}{3} - \dfrac{1}{4}\\
\to - \dfrac{1}{6}x = \dfrac{5}{{12}}\\
\to x = - \dfrac{5}{2}\\
c)x - \dfrac{5}{6}x + \dfrac{x}{3} = 2 - \dfrac{1}{3}\\
\to \dfrac{1}{2}x = \dfrac{5}{3}\\
\to x = \dfrac{{10}}{3}\\
b)\dfrac{{4x - 8 - 6x + 9 - 12\left( {x - 1} \right)}}{{12}} = 0\\
\to - 2x + 1 - 12x + 12 = 0\\
\to 14x = 13\\
\to x = \dfrac{{13}}{{14}}\\
d)\dfrac{{10 - 4x + 3 - 12\left( {x - 1} \right) + 3x - 3}}{6} = 0\\
\to - x + 10 - 12x + 12 = 0\\
\to 13x = 22\\
\to x = \dfrac{{22}}{{13}}
\end{array}\)
