Đáp án:
\( - \dfrac{1}{5}\)
Giải thích các bước giải:
\(\begin{array}{l}
A = \dfrac{{{{\left( {{2^2}} \right)}^5}.{{\left( {{3^2}} \right)}^5} + {2^9}{{.3}^9}.3.2.5}}{{{2^{11}}{{.3}^{11}} - {{\left( {{2^3}} \right)}^4}{{.3}^{12}}}}\\
= \dfrac{{{2^{10}}{{.3}^{10}} + {2^{10}}{{.3}^{10}}.5}}{{{2^{11}}{{.3}^{11}} - {2^{12}}{{.3}^{12}}}}\\
= \dfrac{{{2^{10}}{{.3}^{10}}\left( {1 + 5} \right)}}{{{2^{11}}{{.3}^{11}}\left( {1 - 2.3} \right)}}\\
= \dfrac{6}{{2.3.\left( { - 5} \right)}} = - \dfrac{1}{5}
\end{array}\)
