Em tham khảo nha:
Câu 5:
\(\begin{array}{l}
a)\\
{C_6}{H_{12}}{O_6} \to 2{C_2}{H_5}OH + 2C{O_2}\\
nC{O_2} = \dfrac{{6,72}}{{22,4}} = 0,3\,mol\\
n{C_2}{H_5}OH = nC{O_2} = 0,3\,mol\\
m{C_2}{H_5}OH = 0,3 \times 46 = 13,8g\\
b)\\
n{C_6}{H_{12}}{O_6} = \dfrac{{0,3}}{2} = 0,15\,mol\\
H = 90\% \Rightarrow m{C_6}{H_{12}}{O_6} = \dfrac{{0,15 \times 180}}{{90\% }} = 30g
\end{array}\)
Câu 6:
\(\begin{array}{l}
a)\\
C{H_4} + 2{O_2} \xrightarrow{t^0} C{O_2} + 2{H_2}O\\
{C_2}{H_4} + 3{O_2} \xrightarrow{t^0} 2C{O_2} + 2{H_2}O\\
hh:C{H_4}(a\,ml),{C_2}{H_4}(b\,ml)\\
\left\{ \begin{array}{l}
a + b = 36\\
2a + 3b = 97,2
\end{array} \right.\\
\Rightarrow a = 10,8;b = 25,2\\
\% {V_{C{H_4}}} = \dfrac{{10,8}}{{36}} \times 100\% = 30\% \\
\% {V_{{C_2}{H_4}}} = 100 - 30 = 70\% \\
b)\\
{V_{C{O_2}}} = 10,8 + 25,2 \times 2 = 61,2\,ml
\end{array}\)
