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taovanh2006

2 năm trước

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honghieplc96

a) $\dfrac{1997 x 1996 - 1}{1995 x 1997 + 1996}$

= $\dfrac{(1995+1) x 1997-1}{1995 x 1997+1996}$

= $\dfrac{1995 x 1997+1997-1}{1995x1997+1996}$

= $\dfrac{1996 x 1997+1996}{1995x1997+1996}$

= 1

b) $\dfrac{254 x 399-145}{b}$

= $\dfrac{(1+253) x 399-145}{254+399 x 253}$

= $\dfrac{399 x 254+399-145}{254+399 x 253}$

= $\dfrac{399x253+254}{399x253+254}$

= 1

c) $\dfrac{1997x1996-995}{1996x1997+1002}$

= $\dfrac{(1996+1)x1997-995}{1995x1997+1002}$

= $\dfrac{(1995x1997)+1997-995}{1995x1997+1002}$

= $\dfrac{1995x1997+1002}{1995x1997+1002}$

= 1

d) $\dfrac{2011x2013-1}{2010+2011x2012}$

= $\dfrac{20011x(2012+1)-1}{2010+2011x2012}$

= $\dfrac{2011x2012+2012x1-1}{2010+2011x2012}$

= $\dfrac{2011x2012+2012-1}{2010+2011x2012}$

= $\dfrac{2011x2012+2011}{2010+2012x2011}$

= $\dfrac{1x1+1}{1+1x1}$

= 1

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phuonghienh2k4hv

`a) ( 1997 xx 1996 - 1)/(1995 xx 1997 + 1996)`

`= ( 1997 xx ( 1995 + 1) - 1)/( 1995 xx 1997 + 1996)`

`= ( 1997 xx 1995 + 1997 xx 1 - 1)/( 1995 xx 1997 + 1996)`

`= ( 1997 xx 1995 + 1997 - 1)/( 1995 xx 1997 + 1996)`

`= ( 1997 xx 1995 + 1996)/( 1995 xx 1997 + 1996)`

`=( 1 xx 1+ 1)/( 1 xx 1 + 1)`

`= 1`

`b) ( 254 xx 399 - 145)/( 254 + 399 xx 253)`

`= ( (253+1) xx 399 - 145)/( 254 + 399 xx 253)`

`= ( 253 xx 399 + 399 xx 1 - 145)/( 254 + 399 xx 253)`

`= ( 253 xx 399 + 399 - 145)/( 254 + 399 xx 253)`

`= ( 253 xx 399 + 254)/( 254 + 399 xx 253)`

`= ( 1 xx 1 + 1)/( 1 + 1 xx 1)`

`= 2/2`

`= 1`

`c) ( 1997 xx 1996 - 995)/( 1995 xx 1997 + 1002)`

`= ( 1997 xx ( 1996 + 1) - 995)/( 1995 xx 1997 + 1002)`

`= ( 1997 xx 1996 + 1997 xx 1 - 995)/( 1995 xx 1997 + 1002)`

`= ( 1997 xx 1996 + 1997 - 995)/( 1995 xx 1997 + 1002)`

`= ( 1997 xx 1996 + 1002)/( 1985 xx 1997 + 1002)`

`= ( 1 xx 1 + 1)/( 1 xx 1 + 1)`

`= 1`

`d) ( 2011 xx 2013 - 1)/( 2010 + 2011 xx 2012)`

`= ( 2011 xx ( 2012 + 1) - 1)/( 2010 + 2011 xx 2012)`

`= ( 2011 xx 2012+ 2012 xx 1 - 1)/( 2010 + 2011 xx 2012)`

`= ( 2011 xx 2012 + 2012 - 1)/( 2010 + 2011 xx 2012)`

`= ( 2011 xx 2012 + 2011)/( 2010 + 2011 xx 2012)`

`= ( 1 xx 1 + 1)/( 1 + 1 xx 1)`

`= 1`

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