\(\begin{array}{l}
{x^3} - 3x + 1 = k\left( {x + 2} \right) - 1\\
\Leftrightarrow {x^3} - 3x - kx - 2k + 2 = 0\\
\Leftrightarrow {x^3} - \left( {3 + k} \right)x - 2k + 2 = 0
\end{array}\)
Lược đồ Hooc-ne
\(\begin{array}{*{20}{c}}
{}&1&0&{ - 3 - k}&{ - 2k + 2}\\
\hline
{ - 2}&1&{ - 2}&{1 - k}&0
\end{array}\)