Đáp án:
\(\begin{array}{l}
a.\\
{h_1} = {h_2} = \frac{2}{{15}}m\\
b.\\
{h_1} = {h_2} = \frac{1}{6}m
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a.\\
V = {s_1}{h_1} = {20.10^{ - 4}}.0,4 = {8.10^{ - 4}}{m^3}\\
{v_1} = {h_1}'{s_1} = {20.10^{ - 4}}.{h_1}'\\
{v_2} = {h_2}'{s_2} = {40.10^{ - 4}}{h_2}'\\
V = {v_1} + {v_2}\\
{8.10^{ - 4}} = {20.10^{ - 4}}.{h_1}' + {40.10^{ - 4}}{h_2}'\\
{h_1} = {h_2}\\
\Rightarrow {h_1} = {h_2} = \frac{2}{{15}}m\\
b.\\
V = {s_1}{h_1} + {s_2}{h_2} = {20.10^{ - 4}}.0,4 + {40.10^{ - 4}}.0,05 = {10^{ - 3}}{m^3}\\
{v_1} = {h_1}'{s_1} = {20.10^{ - 4}}.{h_1}'\\
{v_2} = {h_2}'{s_2} = {40.10^{ - 4}}{h_2}'\\
V = {v_1} + {v_2}\\
{10^{ - 3}} = {20.10^{ - 4}}.{h_1}' + {40.10^{ - 4}}{h_2}'\\
{h_1} = {h_2}\\
\Rightarrow {h_1} = {h_2} = \frac{1}{6}m
\end{array}\)
