a) ${4}$-$\frac{1}{2}$x$\frac{3}{5}$
= ${4}$-$\frac{3}{10}$
= $\frac{40}{10}$-$\frac{3}{10}$
= $\frac{37}{10}$
b) $\frac{11}{5}$+(${2}$+$\frac{3}{2}$)
= $\frac{11}{5}$+($\frac{4}{2}$+$\frac{3}{2}$)
= $\frac{11}{5}$+$\frac{7}{2}$
= $\frac{22}{10}$+$\frac{35}{10}$
= $\frac{57}{10}$
c) $\frac{7}{3}$:$\frac{1}{2}$-$\frac{5}{6}$
= $\frac{7}{3}$x$\frac{2}{1}$-$\frac{5}{6}$
= $\frac{14}{3}$-$\frac{5}{6}$
= $\frac{28}{6}$-$\frac{5}{6}$
= $\frac{23}{6}$
$\text{CHÚC EM HỌC TỐT!!}$
