a)
\(\begin{array}{l}
nhh = \frac{{11,2}}{{22,4}} = 0,5\,mol\\
Mhh = 19,6 \times 2 = 39,2g/mol\\
mhh = 39,2 \times 0,5 = 19,6g\\
hh:{O_2}(a\,mol),C{O_2}(b\,mol)\\
32a + 44b = 19,6\\
a + b = 0,5\\
= > a = 0,2b = 0,3\\
m{O_2} = 0,2 \times 32 = 6,4g\\
mC{O_2} = 0,3 \times 44 = 13,2g\\
V{O_2} = 0,2 \times 22,4 = 4,48l\\
VC{O_2} = 0,3 \times 22,4 = 6,72l\\
b)\\
MC{O_2} = M{N_2}O = 44g/mol\\
= > Mhh = 44g/mol\\
dB/{H_2} = \frac{{44}}{2} = 22
\end{array}\)
