Đáp án:
Giải thích các bước giải:
`a.`
`n_{Fe}=\frac{11,2}{56}=0,2(mol)`
`Fe+2HCl->FeCl_2+H_2↑`
`n_{HCl}=2n_{Fe}=0,4(mol)`
`m_{HCl}=0,4.36,5=14,6(g)`
`m_{ddHCl}=14,6:7,3%=200(g)`
`b.`
`n_{FeCl_2}=n_{Fe}=0,2(mol)`
`m_{FeCl_2}=0,2.127=25,4(g)`
`c.`
`n_{H_2}=n_{Fe}=0,2(mol)`
`m_{ddspư}=11,2+200-0,2.2=210,8(g)`
`C%_{ddspư}=\frac{25,4}{210,8}.100=12,05%`
`d.`
`n_{Fe}=\frac{11,2}{56}=0,2(mol)`
`m_{HCl}=300.7,3%=21,9(g)`
`n_{HCl}=\frac{21,9}{36,5}=0,6(mol)`
`Fe+2HCl->FeCl_2+H_2↑`
`\frac{0,2}1<\frac{0,6}2=>HCl\text{ dư}`
`\text{Dung dịch sau phản ứng gồm }FeCl_2\text{ và }HCl\text{ dư}`
`n_{HClpư}=2n_{Fe}=0,4(mol)`
`n_{HCldư}=0,6-0,4=0,2(mol)`
`m_{HCl}=0,2.36,5=7,3(g)`
`n_{FeCl_2}=n_{Fe}=0,2(mol)`
`m_{FeCl_2}=0,2.127=25,4(g)`
`n_{H_2}=n_{Fe}=0,2(mol)`
`m_{ddspư}=11,2+300-0,2.2=310,8(g)`
`C%_{FeCl_2}=\frac{25,4}{310,8}.100=8,172%`
`C%_{HCl}=\frac{7,3}{310,8}.100=2,349%`
`#Devil`
